SOLUTION: Find three consecutive odd integers such that six times the sum of the first and second is 2 more than 10 times the third.

Question 131675: Find three consecutive odd integers such that six times the sum of the first and second is 2 more than 10 times the third.
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
x, x+2 x+4 are the 3 consecutive odd integers.
6(x+x+2)=10(x+4)+2
6(2x+2)=10x+40+2
12x+12=10x+42
12x-10x=42-12
2x=30
x=30/2
x=15 answer for the first odd integer.
15+2=17 the next odd integer
15+4=19 the largest odd integer
proof:
6(15+17)=10*19+2
6*32=190+2
192=192

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