SOLUTION: Find three consecutive integers such that -7 times the sum of the first and third is 12 greater than the product of 10 and the opposite of the second.

Question 1202206: Find three consecutive integers such that -7 times the sum of the first and third is 12 greater than the product of 10 and the opposite of the second.
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!

Find three consecutive integers such that -7 times the sum of the first and third is 12 greater than the product of 10 and the opposite of the second.
let the integers be x,x+1,x+2
-7*(x+x+2) = 10*-(x+1)+12
-7(2x+2) = -10x-10+12
-14x-14 = -10x+2
4x=-16
x=-4
The integers are -4, -3,-2

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