SOLUTION: The smallest of three consecutive integers is 32 less than the sum of the two larger integers. Find the three integers.

SOLUTION: The smallest of three consecutive integers is 32 less than the sum of the two larger integers. Find the three integers.

Algebra.Com

Question 1191174: The smallest of three consecutive integers is 32 less than the sum of the two larger integers. Find the three integers.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
The smallest of three consecutive integers is 32 less than the sum of the two larger integers. Find the three integers.
---------------
n = (n+1) + (n+2) - 32
Solve for n

RELATED QUESTIONS
The smallest of three consecutive integers is 18 less than the sum of the two larger... (answered by stanbon)

The smallest of three consecutive integers is 17 less than the sum of the two larger... (answered by josgarithmetic)

the smallest of three consecutive integers is 18 less than the sum of the two larger... (answered by CubeyThePenguin)

three times the sum of two consecutive integers is three less than two times the larger... (answered by mananth)

one sixth of the smallest of three consecutive even integers is three less than than one... (answered by tommyt3rd)

the greatest of three consecutive integers is 32 less than twice the smallest integer.... (answered by CubeyThePenguin)

Of the three consecutive integers, the sum of the smallest two integers is equal to 33... (answered by elima)

One sixth of the smallest of three consecutive even integers is three less than 1 tenth... (answered by CubeyThePenguin)

one sixth of the smallest of three consecutive even integers is three less than one tenth (answered by CubeyThePenguin)