SOLUTION: Find three consecutive odd integers such that the product of -7and the sum of the first and third is 27 greater than the product of 11 and the opposite of the second. Please help

Question 1158533: Find three consecutive odd integers such that the product of -7and the sum of the first and third is 27 greater than the product of 11 and the opposite of the second. Please help
Answer by Edwin McCravy(20060) (Show Source): You can put this solution on YOUR website!

Least (first) odd integer = x-2
Middle (second) odd integer = x
Greatest (third) odd integer = x+2



Least (first) odd integer = -9-2 = -11
Middle (second) odd integer = -9
Greatest (third) odd integer = -9+2 = -7

Edwin

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