SOLUTION: find three consecutive even integers such that the product of the first and third is 18 greater than the product of -1 and the third.

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Question 1152224: find three consecutive even integers such that the product of the first and third is 18 greater than the product of -1 and the third.
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39628)   (Show Source): You can put this solution on YOUR website!
Even integers n, n+2, n+4

mistake in first step








will not be for even integers.

will give even integers.
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the integers: 2, 4, 6
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Answer by MathTherapy(10556)   (Show Source): You can put this solution on YOUR website!
find three consecutive even integers such that the product of the first and third is 18 greater than the product of -1 and the third.
Let 1st integer be F

Then the 2nd and 3rd are: F + 2, and F + 4, respectively

Then we get the following equation: F(F + 4) = - 1(F + 4) + 18



(F - 2)(F + 7) = 0

F, or 1st integer = 2             OR              F = - 7 (ignore)

You should be able to list the other 2 now!

Note that the other person is WRONG, as usual! 

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