SOLUTION: The product of two consecutive odd integers is twenty-two more than the square of the smallest odd integer.
Algebra
.Com
Question 1150153
:
The product of two consecutive odd integers is twenty-two more than the square of the smallest odd integer.
Answer by
ikleyn(52835)
(
Show Source
): You can
put this solution on YOUR website!
.
n*(n+2) = n^2 + 22
ANSWER
. Since the problem has no question, I do not put my answer here.
RELATED QUESTIONS
The product of two consecutive odd integers is 10 more than the square of the smaller...
(answered by
stanbon,drj
)
Five times the smallest of two consecutive odd integers is the same as twenty-eight more...
(answered by
VFBundy
)
the product of two consecutive odd integers is fourteen more than three times the larger...
(answered by
TimothyLamb
)
The product of two consecutive odd integers is 58 less than the square of the next...
(answered by
mananth
)
4. The Product of two consecutive odd integers is 58 less than the square of the next...
(answered by
josgarithmetic
)
The product of two consecutive odd integers is five more than six times the lesser...
(answered by
Fombitz
)
The product of two consecutive odd integers is equal to 30 more than the first integer....
(answered by
Fombitz
)
The product of two consecutive odd integer is 11 more than twice their sum. Find the two...
(answered by
josgarithmetic
)
The product of three consecutive odd integers is ten less than the cube of the smallest...
(answered by
josgarithmetic
)