SOLUTION: Find three consecutive even integers where the sum of triple the first and twice the second is eight more than four times the third.
____x+___(____)=8(____)______
1x+3(x-2)=8(x
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Question 1145413: Find three consecutive even integers where the sum of triple the first and twice the second is eight more than four times the third.
____x+___(____)=8(____)______
1x+3(x-2)=8(x-4)-3
is what I have I don't think the equation is correct
Answer by josgarithmetic(39631) (Show Source): You can put this solution on YOUR website!
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the sum of triple the first and twice the second is eight more than four times the third.
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first, x
second, x+2
third, x+4
.
.
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