SOLUTION: twice the larger of two consecutive integers is equal to fifteen less than three times the smaller

Question 1125068: twice the larger of two consecutive integers is equal to fifteen less than three times the smaller

Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!

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The two numbers are 17 and 18.
Answer by ikleyn(52803) (Show Source): You can put this solution on YOUR website!
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Let the two consecutive integers be n and (n+1). Then the condition gives you an equation 2*(n+1) = 3n - 15. 2n + 2 = 3n - 15. Add 15 to both sides. 2n + 2 + 15 = 3n. Subtract 2n from both sides 2 + 15 = 3n - 2n, 17 = n. Answer. the two integers are 17 and 18.

You may check it on your own (and it is a good practice to do for every problem you solve) that the conditions of the problem are satisfied.

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