Let "n" be the middle of the three consecutive odd integer numbers. Then the numbers are (n-2), n and (n+2), and their sum is (n-2) + n + (n+2) = 3n. Then the condition says that 3n = 4n - 13. Simplify and solve it: 13 = 4n - 3n ====> 13 = n. Answer. The three numbers are 11, 13 and 15.