SOLUTION: Find three consecutive even integers such that three times the second integer is six more than the sum of the first and third integers.
Algebra.Com
Question 1103753: Find three consecutive even integers such that three times the second integer is six more than the sum of the first and third integers.
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Let the consecutive even integers be:
, , and
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and
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The even integers are 4, 6, and 8
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check:
OK
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