SOLUTION: The sum of 4 times an odd integer and twice the next consecutive odd integer is 46.

SOLUTION: The sum of 4 times an odd integer and twice the next consecutive odd integer is 46.

Algebra.Com

Question 1092654: The sum of 4 times an odd integer and twice the next consecutive odd integer is 46.
Answer by addingup(3677) (Show Source): You can put this solution on YOUR website!
One integer: x
Next consecutive: x+2
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
4x+2(x+2) = 46
4x+2x+4 = 46
6x = 42
x = 7
and the next:
7+2 = 9
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