SOLUTION: The sum of squares of two consecutive positive numbers is 41. Find the two numbers

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Question 1091834: The sum of squares of two consecutive positive numbers is 41. Find the two numbers
Found 3 solutions by Fombitz, Alan3354, MathTherapy:
Answer by Fombitz(32388)   (Show Source): You can put this solution on YOUR website!



Solve for N then find N+1.
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
4 & 5
-----------
41/2 = 20.5
=~ 4.5
--> 4 & 5
====================
There's a hard way, but why bother?
x^2 + (x+1)^2 = 41
Work that out if you like.
Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

The sum of squares of two consecutive positive numbers is 41. Find the two numbers
One number MUST be less than 7 since . It can't be 5 & 6 since their squares total more than 41, so it must be 4 & 5.



If you wish not to go through all of that, then do the following:

Let smaller INTEGER be S

Then larger is S + 1

We then get:  





Complete the solution for S, the smaller integer. 

Add 1 to S to get the larger integer. 

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