SOLUTION: the sum of three integers is 82. the sum of the first and second integers exceeds the third by 86. the third integer is 61 less than the first. find the three integers

Question 1087068: the sum of three integers is 82. the sum of the first and second integers exceeds the third by 86. the third integer is 61 less than the first. find the three integers
Answer by math_helper(2461) (Show Source): You can put this solution on YOUR website!
Giving the answer first in case you'd like to continue to work it out yourself
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Answer: , , and
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Workout:

A + B + C  = 82     (1)
A + B  = C + 86     (2)
C = A - 61          (3)


I chose to substitute "C+86" from (2) as "A+B" in (1):

(C + 86) + C = 82  ==>  2C = -4 ==>   C = -2

Plugging this result into (3) gives  A = 59
Plugging the newly found A & C values into (1) or (2) gives  B = 25

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Check:  A + B + C = 59 + 25 - 2 = 82   (ok)
             A + B = 59 + 25 = 84   and    C + 86 = -2 + 86 = 84    (ok)
             C = -2   and     A-61 = 59-61 = -2  (ok)

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