SOLUTION: A positive real number is 6 less than another. If the sum of the squares of the two numbers is 66, find the numbers.
Algebra.Com
Question 1077588: A positive real number is 6 less than another. If the sum of the squares of the two numbers is 66, find the numbers.
Answer by jorel1380(3719) (Show Source): You can put this solution on YOUR website!
Let the first number be n. Then the 2nd number is n-6. So:
n²+(n-6)²=66
n²+n²-12n+36-66=0
2n²-12n-30=0
n²-6n-15=0
Using the quadratic formula, we get a positive value of 7.89897948557 as n. Then n-6 would be 1.89897948557. ☺☺☺☺
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