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I think that Candace's best strategy (winning strategy) is to maintain the difference of 0 between the number of beans in two piles.
Following to this strategy, Candace's next (closest) step is to remove 2 beans from the 27-beans pile.
So, Candace will achieve his strategic goal at the first step, and after any step of his partner Candace can maintain the difference of 0.
By doing in this way, whichever number of beans will Darryl remove from one container, the same number of beans will Candace
remove from the other container, maintaining the number of beans the same in both containers.
By doing in this way, he will FORCE Darryl to remove, finally, the last bean (or the last portion of beans) from one of
the two containers at Darryl's current step.
Then Candace wins the game at his next (=last) turn removing the same number of remaining beans from the other container.
Solved.