SOLUTION: Find two consecutive even integers such that twice the smaller is 16 more than the larger.

SOLUTION: Find two consecutive even integers such that twice the smaller is 16 more than the larger.

Algebra.Com

Question 1073195: Find two consecutive even integers such that twice the smaller is 16 more than the larger.
Answer by jorel1380(3719) (Show Source): You can put this solution on YOUR website!
Let n be the smaller integer. Then the larger integer is n+2. So:
2n=n+2+16
n=18
The smaller integer is 18; the larger one is 20. ☺☺☺☺
RELATED QUESTIONS
Find two consecutive even integers such that twice the smaller is 10 more than the larger (answered by fractalier)

Find two consecutive integers such that twice the smaller is 16 more than the... (answered by ad_alta)

Find two consecutive even integers such that three times the smaller is 30 more than... (answered by richwmiller,Fombitz)

I'm having trouble with this problem: Find two consecutive even integers such that twice... (answered by Fombitz)

Find two consecutive integers such that twice the smaller is two more than the... (answered by CubeyThePenguin)

Find two consecutive odd integers such that twice the larger is 17 more than the... (answered by QH)

Find two consecutive odd integers such that twice the larger is 17 more than the... (answered by mananth)

find two consecutive integers such that the larger is nine more than twice the smaller. (answered by JulietG)

Find two consecutive integers such that the larger is nine more than twice the smaller (answered by toddcarnes)