SOLUTION: Find three consecutive odd positive integers such that five times the sum of all three is 72 more than the product of the first and second integers .

SOLUTION: Find three consecutive odd positive integers such that five times the sum of all three is 72 more than the product of the first and second integers .

Algebra.Com

Question 1072634: Find three consecutive odd positive integers such that five times the sum of all three is 72 more than the product of the first and second integers .
Answer by josgarithmetic(39616) (Show Source): You can put this solution on YOUR website!
The integers,

-

Discriminant, ,.... or,

and the description specified ODD integers.

The consecutive odd positive integers: 7, 9, 11
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