SOLUTION: Find three biggest consecutive natural number such that sum of twice the first and three more than the third is at most 25
Algebra.Com
Question 1069061: Find three biggest consecutive natural number such that sum of twice the first and three more than the third is at most 25
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
consecutive integers: (x-1), x, (x+1)
2(x - 1) + (x + 1) + 3 <= 25
2x - 2 + x + 4 <= 25
3x <= 23
x <= 23/3 = 7.66
The largest possible values of the integers are 6, 7, and 8.
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