SOLUTION: Find the biggest of three consecutive odd numbers such that the product of the second and third is greater than the square of the first by 110

Question 1068646: Find the biggest of three consecutive odd numbers such that the product of the second and third is greater than the square of the first by 110
Answer by htmentor(1343) (Show Source): You can put this solution on YOUR website!
Let the 3 integers be n, n+2 and n+4
Product of 2nd and 3rd is greater than the square of the first by 110. In equation form this is:
(n+2)(n+4) = n^2 + 110
Expand and simplify:
n^2 + 6n + 8 = n^2 + 110
6n = 102 -> n = 17
So the integers are 17, 19, and 21.
The largest of these is 21.
Ans: 21
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