SOLUTION: Three consecutive integers are such that the first integer plus twice the second integer plus five less than the third integer is 27. What are the integers?

Question 1065665: Three consecutive integers are such that the first integer plus twice the second integer plus five less than the third integer is 27. What are the integers?
Answer by addingup(3677) (Show Source): You can put this solution on YOUR website!
x+2(x+1)+x+2-5 = 27
x+2x+2+x-3 = 27
group like terms (it doesn't change the result, but it's better/easier)
2x+x+x+2-3 = 27
4x-1 = 27
4x = 28
x = 7
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Check:
7+2(8)+(9-5) = 27
7+16+4 = 27 Correct.
:
John
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