n = first integer n+1 = second integer n+2 = third integer n+3 = fourth integer
n+(n+1)+(n+2)+(n+3) = X
n+n+1+n+2+n+3 = X
4n+6 = X
4n = X-6
n =
n+1 = second integer =
n+2 = third integer =
What is the sum of the second and third integers?
Edwin