SOLUTION: find three consecutive integers such that the sum of the first, twice the second, and three times the third is -76

Question 1062848: find three consecutive integers such that the sum of the first, twice the second, and three times the third is -76

Answer by Edwin McCravy(20060) (Show Source): You can put this solution on YOUR website!

first integer = n
second integer = n+1
third integer = n+2

n + 2(n+1) + 3(n+2) = -76

Solve that and you will get a negative number.
Then find the second and third integers. They will
all be negative numbers.

Edwin

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