x+y = x×y = x²-y²

Obviously x = 0 = y is a solution.

if x+y = x²-y² then











; 

;   

But we have to make sure that



For the first case 







So one solution is x = y = 0, the obvious one.

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For the second case 























For 







So a second solution is:

,  

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For 







So a third solution is:

,  

Edwin