SOLUTION: Using algebra, find the smallest three consecutive integers whose sum is greater than 20 What in did is x+x+1+x+2>20 3x+3>20 3x>30 then I'm stuck

Question 1061156: Using algebra, find the smallest three consecutive integers whose sum is greater than 20
What in did is x+x+1+x+2>20
3x+3>20
3x>30 then I'm stuck
Answer by ikleyn(53937) (Show Source): You can put this solution on YOUR website!
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Using algebra, find the smallest three consecutive integers whose sum is greater than 20
What in did is x+x+1+x+2>20
3x+3>20
3x>30 then I'm stuck
~~~~~~~~~~~~~~~~~~~~~~~~

x + x+1 + x+2 > 20

3x  + 3 > 20,

3x > 20-3,

3x > 17.

The solution in integer numbers is  x >= 6.


Thus your triples are (6, 7, 8),  (7, 8, 9),  (8, 9, 10) . . . and so on.

The smallest triple is (6, 7, 8) with the sum of 21.

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