SOLUTION: Find three consecutive odd natural numbers such that the product of the first and the last is 11 greater than two times the middle one.

Question 1058067: Find three consecutive odd natural numbers such that the product of the first and the last is 11 greater than two times the middle one.
Answer by jorel555(1290) (Show Source): You can put this solution on YOUR website!
Let n be the first odd number. Then the next numbers in sequence will be n+2 and n+4. So:
n(n+4)=2(n+2)+11
n�+4n=2n+15
n�+2n-15=0
(n+5)(n-3)=0
n=3 or -5
Throwing out the negative answer, we get the consecutive odd numbers as 3, 5, and 7. ☺☺☺☺
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