SOLUTION: the sum of two integers is 64. one integer is 20 less than twice the other. find the smaller integer.

Algebra.Com
Question 1057221: the sum of two integers is 64. one integer is 20 less than twice the other. find the smaller integer.

Answer by addingup(3677)   (Show Source): You can put this solution on YOUR website!
x+y = 64
x = 2y-20
2y-20+y = 64
3y = 84
y = 28 this is y, and x:
x = 2y-20 = 2(28)-20 = 56-20 = 36
------------------------------
Check:
28+36 = 64 Correct
:
john

RELATED QUESTIONS

The sum of two integers is 64. One integer is 20 less than twice the other. Find the... (answered by fractalier)
The sum of two integers is 25. One less than twice the larger integer is equal to one... (answered by ikleyn)
One-fifth of sum of two consecutive integers is 64 less than the smaller integer. Find... (answered by jorel1380)
An integer is seven more than another integer. Twice the larger integer is one less than... (answered by mananth)
the sum of two integers is fifty seven. Twice the smaller integer is six less than the... (answered by hamsanash1981@gmail.com)
The sum of two integers is 23. If the larger integer is one less than twice the smaller,... (answered by stanbon)
the sum of 2 integers is 25. One less than twice the larger integer is equal to one more... (answered by CubeyThePenguin)
One integer is 2 more than another integer. The sum of the two integers is 48. Find the... (answered by Maths68)
An integer is three more than another integer. Twice the larger integer is two less than... (answered by CubeyThePenguin)