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Two airplanes depart from an airport traveling in opposite directions. The second airplane is 200 miles per hour faster
than the first. After 2 hours they are 1100 miles apart. Find the speeds of the airplanes?
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2*(x + (x+200)) = 1100. (It is the "distance" equation D = R*T)
(Here "x" is the speed of the slowest plane)
Simplfy and solve for x:
2x + 2x + 400 = 1100 --->
4x = 1100-400,
4x = 700 ---> x = = 175 mph.
Answer. The speed of the slowest plane is 175 mph.
The speed ot the other plane is 175+200 = 375 mph.
Check. 2*(175+375) = 2*550 = 1100. Correct!