SOLUTION: The square of sum of the two successive uneven numbers is 64.calculate the value ofthese numbers

Question 1053961: The square of sum of the two successive uneven numbers is 64.calculate the value ofthese numbers
Found 3 solutions by algebra hello, MathTherapy, ikleyn:
Answer by algebra hello(55)   (Show Source): You can put this solution on YOUR website!
let two successive uneven numbers are x,x+2 then (x+x+2)^2=64 (2x+2)^2=64 4(x+1)^2=64 (x+1)^2=16 x+1=4 x=3 so the numbers are 3,5
Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

The square of sum of the two successive uneven numbers is 64.calculate the value ofthese numbers

Answer by ikleyn(52780)   (Show Source): You can put this solution on YOUR website!
.
The easiest way to solve this problem is to notice that, due to the condition, the sum
of these two numbers is +8 or -8.

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