SOLUTION: Find four consecutive even integers such that two times the sum of the first and second is 40 more than three times the fourth explain

Question 1053483: Find four consecutive even integers such that two times the sum of the first and second is 40 more than three times the fourth explain
Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!
Let , , and be the four consecutive even integers.
So,
= the sum of the first and second integers,
= two times the sum of the first and second integers,
= three times the fourth integer, and
= 40 more than three times the fourth integer.
The problem says that
,
and that is the equation we have to solve.

So the four consecutive even integers are
, , and .

Verification:
The sum of the first and second integers is .
Two times the sum of the first and second integers is .
Three times the fourth integer is .
Forty (40) more than three times the fourth integer is .
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