SOLUTION: the sum of three consecutive numbers is 41 less than 5 times the largest number. find the largest number.

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Question 1050356: the sum of three consecutive numbers is 41 less than 5 times the largest number. find the largest number.
Answer by advanced_Learner(501)   (Show Source): You can put this solution on YOUR website!
the sum of three consecutive numbers is 41 less than 5 times the largest number. find the largest number.
x + x+1 +x+2=-41+5x+10
-2x=-41+7
Solved by pluggable solver: EXPLAIN simplification of an expression
Your Result:


YOUR ANSWER


  • This is an equation! Solutions: x=17.
  • Graphical form: Equation was fully solved.
  • Text form: -2x=-41+7 simplifies to 0=0
  • Cartoon (animation) form:
    For tutors: simplify_cartoon( -2x=-41+7 )
  • If you have a website, here's a link to this solution.

DETAILED EXPLANATION

Look at .
Added fractions or integers together
It becomes .
Look at .
Removed extra sign in front of -34
It becomes .
Look at .
Moved these terms to the left highlight_green%28+34+%29
It becomes .
Look at .
Solved linear equation highlight_red%28+-2%2Ax%2B34=0+%29 equivalent to -2*x+34 =0
It becomes .
Result:
This is an equation! Solutions: x=17.

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Done!


x=
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