SOLUTION: Find the smaller of two consecutive integers such that differences of 4 times the first number and 2 times the second number is 40

SOLUTION: Find the smaller of two consecutive integers such that differences of 4 times the first number and 2 times the second number is 40

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Question 1049971: Find the smaller of two consecutive integers such that differences of 4 times the first number and 2 times the second number is 40
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
n and (n+1) , the two consecutive integers
4x - 2(n+1) = 40
2n = 42
n = 21
21 and 22 the two consecutive integers
84 + 44 = 40 CHECKS!
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