SOLUTION: Find two consecutive even integers such that the sum of twice the lesser and three times the greater is 66.

Question 1049905: Find two consecutive even integers such that the sum of twice the lesser and three times the greater is 66.
Found 2 solutions by ewatrrr, MathLover1:
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
two consecutive even integers: x and (x+2)
2x + 3(x+2) = 66
5x = 60
x = 12
The two consecutive even integers are: 12 , 14
AND
24 + 42 = 66 CHECKS!

Answer by MathLover1(20851) (Show Source): You can put this solution on YOUR website!
Lets call the first integer .
For the second integer to be a consecutive even interger it must be }
so far we have:
first interger =
second interger =
if given that the sum of the and times the is , we have
...............solve for

and, second one is

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