SOLUTION: I do not know how to solve this problem: Find three consecutive integers, such that the sum of the largest and twice the smallest is 41. I know that the first number will be repr

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: I do not know how to solve this problem: Find three consecutive integers, such that the sum of the largest and twice the smallest is 41. I know that the first number will be repr      Log On


   



Question 1048050: I do not know how to solve this problem: Find three consecutive integers, such that the sum of the largest and twice the smallest is 41. I know that the first number will be represented by x. I also know that 41 comes after the equals sign.
Found 2 solutions by josmiceli, advanced_Learner:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let the consecutive integers be:
+n+, +n%2B1+, and +n%2B2+
------------------------------
+n%2B+2+%2B+2n+=+41+
+3n+=+39+
+n+=+13+
and
+n+%2B+1+=+14+
+n+%2B+2+=+15+
----------------
The numbers are 13, 14, and 15
----------------
check:
+n%2B+2+%2B+2n+=+41+
+15+%2B+2%2A13+=+41+
+15+%2B+26+=+41+
+41+=+41+
OK

Answer by advanced_Learner(501) About Me  (Show Source):
You can put this solution on YOUR website!
x+x+1+x+2
x+2 + 2x=41
3x=39
x=13
13 14 15