SOLUTION: I do not know how to solve this problem: Find three consecutive integers, such that the sum of the largest and twice the smallest is 41. I know that the first number will be repr
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Question 1048050: I do not know how to solve this problem: Find three consecutive integers, such that the sum of the largest and twice the smallest is 41. I know that the first number will be represented by x. I also know that 41 comes after the equals sign.
Found 2 solutions by josmiceli, advanced_Learner:
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Let the consecutive integers be:
, , and
------------------------------
and
----------------
The numbers are 13, 14, and 15
----------------
check:
OK
Answer by advanced_Learner(501) (Show Source): You can put this solution on YOUR website!
x+x+1+x+2
x+2 + 2x=41
3x=39
x=13
13 14 15
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