SOLUTION: The sum of the two smallest of five consecutive odd integers is 21 less than the sum of the other three integers. What is the smallest integer?

Question 1046910: The sum of the two smallest of five consecutive odd integers is 21 less than the sum of the other three integers. What is the smallest integer?
Found 2 solutions by addingup, advanced_Learner:
Answer by addingup(3677) (Show Source): You can put this solution on YOUR website!
x+x+2+x+4+x+6+x+8 = x+1+x+3+x+5+21
5x+20 = 3x+30
2x = 10
x = 5 this is the smallest integer
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Check:
5+7+9+11+13 = 6+8+10+21
45 = 45 Correct

Answer by advanced_Learner(501) (Show Source): You can put this solution on YOUR website!
x-4 x-2 x x+2 x+4 five con odd integers.

x-4 and x-2 are the smallest
(x-4)+(x-2)=(x)+(x+2)+(x+4) -21
2x-6=3x-15
x=9
the numbers are 5 7 9 11 13
the smallest is 5

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