SOLUTION: Find two consecutive odd integers such that 86 more than the lesser is five times the greater

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Question 1045799: Find two consecutive odd integers such that
86
more than the lesser is
five
times the greater
Found 2 solutions by ewatrrr, MathTherapy:
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
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Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!
Find two consecutive odd integers such that
86
more than the lesser is
five
times the greater
Let smaller integer be S

Then larger is: S + 2

We then get: S + 86 = 5(S + 2)

Solve for S to get the smaller of the 2

Add 2 to the smaller to get the larger, and you're done! 

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