SOLUTION: The sum of three consecutive numbers is 41 less than five times the largest number. What is the largest number?

Question 1045417: The sum of three consecutive numbers is 41 less than five times the largest number. What is the largest number?
Found 3 solutions by josgarithmetic, advanced_Learner, MathTherapy:
Answer by josgarithmetic(39625)   (Show Source): You can put this solution on YOUR website!

Answer by advanced_Learner(501)   (Show Source): You can put this solution on YOUR website!
=
Answer by MathTherapy(10555)   (Show Source): You can put this solution on YOUR website!

The sum of three consecutive numbers is 41 less than five times the largest number. What is the largest number?

Let largest number be L
Then smallest and middle are: L - 2, and L - 1, respectively
We then get: L - 2 + L - 1 + L = 5L - 41
3L - 3 = 5L - 41
3L - 5L = - 41 + 3
- 2L = - 38
L, or largest = =
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