SOLUTION: The sum of two numbers is 118.
  
If three times
the smaller number is subtracted from the larger​ number, the result is 18.
  
Find the two n
Algebra.Com
Question 1038552: The sum of two numbers is 118.
If three times
the smaller number is subtracted from the larger number, the result is 18.
Find the two numbers.
Found 2 solutions by addingup, solver91311:
Answer by addingup(3677) (Show Source): You can put this solution on YOUR website!
x+y =118
x-3y = 18 multiply all by -1 and add to the other equation:
````````````````````````````````````````````````````
x+y = 118
+
-x+3y = -18
4y = 100
y = 25
Now let's find x:
x-3y = 18
x-3(25) = 18
x-75 = 18
x = 93
Check
x+y = 118
93+25 = 118 Correct.
John
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Solve for 
and 
. Hint: Multiply the 2nd equation by -1 and then use elimination.
John
My calculator said it, I believe it, that settles it
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