SOLUTION: Find two consecutive odd integers such that their product is 71 more than 7 times their sum

SOLUTION: Find two consecutive odd integers such that their product is 71 more than 7 times their sum

Algebra.Com

Question 1034566: Find two consecutive odd integers such that their product is 71 more than 7 times their sum
Answer by jorel555(1290) (Show Source): You can put this solution on YOUR website!
let n be your first integer; your second integer is n+2:
n(n+2)=7(n+n+2)+71
n^2+2n=14n+85
n^2-12n-85=0
(n-17)(n+5)=0
n=17
n+2=19!!!!!!!!
RELATED QUESTIONS
Find two consecutive odd integers such that their product is 31 more than 7 times their... (answered by Alan3354)

Find two consecutive odd integers such that their product is 119 more than 7 times their... (answered by Boreal)

find two consecutive odd integers such that their product is 15 more than 3 times their... (answered by drj)

Find two consecutive odd integers such that their product is 79 more than 8 times their... (answered by macston)

Find two consecutive odd integers such that their product is 35 more than 8 times their... (answered by KMST,MathTherapy)

Find two consecutive odd integers such that their product is 31 more than 2 times (answered by solver91311)

Find two consecutive odd integers such that their product is 95 more than 5 times their... (answered by frcasem)

Question Help Find two consecutive odd integers such that their product is 107 more (answered by solver91311)

Find two consecutive odd integers such that their product is 47 more than 4 times their... (answered by Boreal)