SOLUTION: the sum of five consecutive even integers exceeds four times the second number by 20.find the smallest number?
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Question 1031990: the sum of five consecutive even integers exceeds four times the second number by 20.find the smallest number?
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
n+(n+2)+(n+4)+(n+6)+(n+8)=4(n+2)+20
5n +20 = 4(n+2) +20
5n = 4n +8
n=8
8,10,12,14,16
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