SOLUTION: find four consecutive odd intergers such that the sum of the second and the fourth is 17 more than one half the sum of the first and the third
Algebra.Com
Question 1018748: find four consecutive odd intergers such that the sum of the second and the fourth is 17 more than one half the sum of the first and the third
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
4 consecutive odd integers: x, (x+2), (x+4), (x+6)
(x+2) + (x+6) = 17 + 1/2 * (x + (x+4))
2x + 8 = 17 + x + 2
x = 11
The integers are 11, 13, 15, and 17.
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