SOLUTION: If three consecutive integers are such that three times the smallest is 12 more than the largest?

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Question 1014805: If three consecutive integers are such that three times the smallest is 12 more than the largest?
Answer by FrankM(1040)   (Show Source): You can put this solution on YOUR website!
3 consecutive integers are X, X+1, X+2.
3X=(X+2)+12 >>> (three times the smallest is 12 more than the largest)
3X=X+14
2X=14
X = 7
7,8,9
21 is 12 more than 9.

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