SOLUTION: Find three consecutive odd intergers such that the sum of the first and twice the third is the same a thirty-two more than the second

SOLUTION: Find three consecutive odd intergers such that the sum of the first and twice the third is the same a thirty-two more than the second

Algebra.Com

Question 1013145: Find three consecutive odd intergers such that the sum of the first and twice the third is the same a thirty-two more than the second
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
Call them x, x+2, and x+4. Then we have
x + 2(x+4) = 32 + (x+2)
3x + 8 = x + 34
2x = 26
x = 13
The numbers are
13, 15, and 17.
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