SOLUTION: What is the sum of the terms in an arithmetic progression obtained by inserting 7 arithmetic means between 3 and 35?

Algebra.Com
Question 1003397: What is the sum of the terms in an arithmetic progression obtained by inserting 7 arithmetic means between 3 and 35?
Answer by CubeyThePenguin(3113)   (Show Source): You can put this solution on YOUR website!
3, __, __, __, __, __, __, __, 35

difference: (35 - 3)/8 = 4

terms: 3 + 7 + 11 + 15 + 19 + 23 + 27 + 31 + 35 = 171

RELATED QUESTIONS

A geometric progression has six terms. The first term is 486 and the common ratio is ;.... (answered by greenestamps)
There are 9 arithmetic means between 11 and 51. The sum of the progression... (answered by Edwin McCravy)
If there are 12 arithmetic means between -5 and 60, what is the common difference of the... (answered by ikleyn)
A geometric progression has 6 terms. The first term is 192 and the common ratio is 1.5.... (answered by greenestamps)
The first and the last term of an arithmetic progression are 9 and 93.If the sum of the... (answered by mananth,stanbon)
The sum of first 3 integers in an Arithmetic progression is 36. The sum of the next 3... (answered by stanbon)
The sum of first 3 integers in an Arithmetic progression is 36. The sum of the next 3... (answered by math_helper)
The sum of the first 10 terms of an arithmetic progression is 80 and the sum of the next... (answered by jitendra_maths,mananth)
The arithmetic progression consists of 15 terms. If the sum of the 3 terms in the middle (answered by ikleyn)