SOLUTION: The product of three consecutive odd integers is ten less than the cube of the smallest odd integer.

Question 1001799: The product of three consecutive odd integers is ten less than the cube of the smallest odd integer.
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
You can try n, n+2, n+4 as the "odd" integers and see what happens.
. Solve for n. Does this work?

-
(3n 1)(n 5) NO
(3n 5)(n 1) NO
-
Use formula for quadratic general solution
---NO because discriminant is negative.

Try ensuring that the numbers are ODD.
They should be like 2n+1, 2n+3, 2n+5.
The description:

A few more simplifications steps,

NOW, plug values into general solution formula for a quadratic equation and begin simplifying:

Notice that the discriminant IS NEGATIVE.
NO SOLUTION

RELATED QUESTIONS
The sum of three consecutive odd integers is 17 less than four times the smallest... (answered by ankor@dixie-net.com)

The sum of three consecutive odd integers is 17 less than four times the smallest... (answered by CubeyThePenguin)

The product of two consecutive odd integers is 58 less than the square of the next... (answered by mananth)

Five times the second of three consecutive odd integers is thirteen less than three times (answered by josmiceli)

The product of two consecutive odd integers is twenty-two more than the square of the... (answered by ikleyn)

the sum of three consecutive odd integers is 5 less than 4 times the smallest such... (answered by Fombitz)

The sum of 3 consecutive odd integers is 17 less than 4 times the smallest integer (answered by CubeyThePenguin)

The sum of the two smallest of five consecutive odd integers is 21 less than the sum of... (answered by addingup,advanced_Learner)

Find three consecutive integers whos product is 120 larger than the cube of the smallest... (answered by solver91311)