SOLUTION: three consecutive integers such that the sum of the largest and 5 times the smallest is -244
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Question 1001401: three consecutive integers such that the sum of the largest and 5 times the smallest is -244
Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
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S=smallest; M=middle=S+1; L=large=S+2
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L+5S=-244
(S+2)+5S=-244
6S=-246
S=-41
ANSWER 1: Smallest is -41
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M=S+1=-41+1=-40
ANSWER 2: Middle is -40
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L=S+2=-41+2=-39
ANSWER 3: Large is -39
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CHECK:
L+5S=-244
-39 +5(-41)=-244
-39-205=-244
-244=-244
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