Problem: With a pair of fair dice, what is the probability that a single roll will have a total of at least 10?
.
Solution: Probability always is based on the number of favorable outcomes divided by the total possible outcomes. With 2 dice there are 36 possible outcomes for any roll: 6*6 =36. The following table shows the possible sums:
.
| Die 1 |
| Die 2 |
| | 1 | 2 | 3 | 4 | 5 | 6 |
| 1 | 2 | 3 | 4 | 5 | 6 | 7 |
| 2 | 3 | 4 | 5 | 6 | 7 | 8 |
| 3 | 4 | 5 | 6 | 7 | 8 | 9 |
| 4 | 5 | 6 | 7 | 8 | 9 | 10 |
| 5 | 6 | 7 | 8 | 9 | 10 | 11 |
| 6 | 7 | 8 | 9 | 10 | 11 | 12 |
The question is what is the probability the sum is at least 10. Inspecting this table, you can see that:
1 of these 36 outcomes = 12
2 of these 36 outcomes = 11
3 of these 36 outcomes = 10
.
Answer: The probability that the sum will be 10 or more is:
.
P(10 or more) = 6/36 = 1/6
.
This result may be expressed as about 16.67%.
This lesson has been accessed 351 times.