Tutors Answer Your Questions about Probability-and-statistics (FREE)
Question 210083: The bank of of Hawaii reported that 7% of its credit card holders will default at some time in their life. the Hilo branch just mailed out 12 new card
what is the likelywood that none of the card holder will default
what is the likelyhood that at least one will default
Click here to see answer by stanbon(57285) |
Question 210184: The bank of of Hawaii reported that 7% of its credit card holders will default at some time in their life. the Hilo branch just mailed out 12 new card
what is the likelywood that none of the card holder will default
A)How many of these cards do you expect to default? What is the standard deviation
B) What is the likelyhood that none of the card holder will default
C) What is the likelyhood that at least one will default
Click here to see answer by stanbon(57285) |
Question 210180: A plant manager at a local factory makes widgets, and he wants to propose a more efficient manufacturing process. He would like you to find the estimate time it takes to make the widget under the new proposal. So far, he has some data that says the fastest widget production time is 500 seconds, and the slowest is 560 seconds. He would like to estimate the mean assembly time to within 4 seconds with a 95% confidence interval but questions what sample size he'll need to have. Assume that the widget assembly times are normally distributed. Can you recommend a sample size for him?
Click here to see answer by stanbon(57285) |
Question 210376: i can not figure this one out. can someone just tell me how to calculate.7 of 20,000. i get 14000 and that would only leave 6,000 which isnt an option. help please!!!
A contractor is considering a sale that promises a profit of $ 20,000 with a probability of .7 or a loss (due to bad weather, strikes, and such) of $ 3000 with a probability of .3. What is the expected profit?
A)
$ 16,100
B)
$ 17,000
C)
$ 13,100
D)
$ 14,000
Click here to see answer by vleith(2825) |
Question 210376: i can not figure this one out. can someone just tell me how to calculate.7 of 20,000. i get 14000 and that would only leave 6,000 which isnt an option. help please!!!
A contractor is considering a sale that promises a profit of $ 20,000 with a probability of .7 or a loss (due to bad weather, strikes, and such) of $ 3000 with a probability of .3. What is the expected profit?
A)
$ 16,100
B)
$ 17,000
C)
$ 13,100
D)
$ 14,000
Click here to see answer by tutor_paul(490)  |
Question 210399: A lottery game has balls numbered 1 through 15. What are the odds of selecting an even numbered ball or a 8?
i need help beacsue i am confused how both answers can be the same. numbers 1-15 have 7 even numbers in between meaning this probabilty would be 7:15 but getting an 8 out of 1-15, wouldnt that be 1:8? the choices are between-
A)
15 : -7
B)
7 : 8
C)
7 : 15
D)
8 : 7
Click here to see answer by stanbon(57285) |
Question 210756: Last fall, a gardener planted 74 tulip bulbs. She found that only 62 of the bulbs bloomed in the spring.
a) Find the empirical probability that a tulip bulb of this type will bloom
b) How many of the bulbs should she plant next fall if she would like at least 95 to bloom?
Click here to see answer by tutor_paul(490)  |
Question 210766: Please help me in this question:(Hypothesis Testing on Two Samples)
A sample of 14 cans of Coke diet soda gave the mean number of calories of 23 per can with a standard deviation of 3 calories. Another sample of 16 cans of Pepsi diet soda gave the mean number of calories of 25 per can with standard deviation of 4 calories. at the 1% significance level, can you conclude that the mean numbers of calories per can are different for these two brands of diet soda? Assume that the calories per can of diet soda are normally distributed for each of the two brands and that the standard deviations for the two population are equal.
Click here to see answer by stanbon(57285) |
Question 210776: This is from the textbook Statistical Techniques in Business and Economics, 13th edition, exercise #34
Information from the American Institute of Insurance indicates the mean amount of life insurance per household in the Unites States is $110,00. This distribution follows the normal distribution with a standard deviation of $40,000.
if we select a random sample of 50 households what is the standard error of the mean
what is the expected shape of the distribution of the sample mean
what is the likelihood of selecting a sample with a mean of at least $112,000
what is the likelihood of selecting a sample with a mean of more than $100,00
find the likelihood of selecting a sample with a mean of no more than $100,000 but no less than $112,000.
Click here to see answer by stanbon(57285) |
Question 210870: EDITORIAL CORRECTION OF THE TABLE:
The problem is as stated: Use the data in the following table, which summarizes blood groups and Rh types for 100 subjects. These values may vary in different regions according to the ethnicity of the population.
------------------Group
-----------------A---B--AB--O
Type--Rh(+)---39--35--8--4
--------Rh(-)---6---5---2--1
Blood groups and types If 2 of the 100 subjects are randomly selected find the probability that they are both group O and type Rh+.
A. Assume that the selections are made with replacement.
B. Assume that the selections are made without replacement.
Click here to see answer by stanbon(57285) |
Question 210872: One study found that 8% of men and 0.5% of women are born color-bline. Of the study participants, 52% were men.
What is the probability that a study participant is male and born color-blind?
What is the probability that a study participant is male or born color-blind?
Click here to see answer by stanbon(57285) |
Question 210920: This Question is from Applied Statistics and is Question 13.30 I have read page 591 nad 592 I still don't understand it has it been answered before on here? I really need some help on this question. Thank you
Click here to see answer by stanbon(57285) |
Question 211071: A contractor is considering a sale that promises a profit of $20,000 with a probability of .7 or a loss (due to bad weather, strikes, and such) of $3000 with a probability of .3. What is the expected profit?
Click here to see answer by edjones(7569)  |
Question 211120: A researcher predicts that listening to music while solving math problems will
make a particular brain area more active. To test this, a research participant has
her brain scanned while listening to music and solving math problems, and the
brain area of interest has a percent signal change of 58. From many previous
studies with this same math-problems procedure (but not listening to music), it
is known that the signal change in this brain area is normally distributed with a
mean of 35 and a standard deviation of 10. Using the .01 level, what should the
researcher conclude? Solve this problem explicitly using all five steps of
hypothesis testing, and illustrate your answer with a sketch showing the comparison
distribution, the cutoff (or cutoffs), and the score of the sample on this
distribution. Then explain your answer to someone who has never had a course
in statistics (but who is familiar with mean, standard deviation, and Z score
Click here to see answer by stanbon(57285) |
Question 211177: It is the last week of class and I think I am finally totally brain dead. I have stared blankly at this problem for over an hour, feably making an attempt to solve it to no avail despite the fact that I have solved two others. Please help me with this problem. I can't seem to find anything about it on your website (not, dashes are column data dividers, not negatives or subtraction). Thank you!!!!!
(a) Plot the data on U.S. general aviation shipments.
(b) Describe the pattern and discuss possible causes.
(c) Would a fitted trend be helpful? Explain.
(d) Make a similar graph for 1992–2003 only. Would a fitted trend be helpful in making a prediction for 2004? (e) Fit a trend model of your choice to the 1992–2003 data.
(f) Make a forecast for 2004, using either the fitted trend model or a judgment forecast. Why is it best to ignore earlier years in this data set?
U.S. Manufactured General Aviation Shipments, 1966–2003
Year -Planes -Year -Planes -Year -Planes -Year -Planes
1966 -15,587 -1976 -5,451 -1986 -1,495 -1996 -1,053
1967 -13,484 -1977 -16,904 -1987 -1,085 -1997 -1,482
1968 -13,556 -1978 -17,811 -1988 -1,143 -1998 -2,115
1969 -12,407 -1979 -17,048 -1989 -1,535 -1999 -2,421
1970 -7,277 -1980 -11,877 -1990 -1,134 -2000 -2,714
1971 -7,346 -1981 -9,457 -1991 -1,021 -2001 -2,538
1972 -9,774 -1982 -4,266 -1992 -856 -2002 -2,169
1973 -13,646 -1983 -2,691 -1993 -870 -2003 -2,090
1974 -14,166 -1984 -2,431 -1994 -881
1975 -14,056 -1985 -2,029 -1995 -1,028
Click here to see answer by stanbon(57285) |
Question 211223: Someone Please Help, with this solution
A card is selected from a deck of 52 playing cards. Find the probability of selecting
A) a seven given the card is not a face card (An ace is not a face card)
B) a spade given the card is red
Click here to see answer by nerdybill(6955)  |
Question 211222: Please Help me find the step by step solution to this question
A box of chocolates contains 20 identically shaped chocolates. Four of them are filled with jelly, seven are filled with caramel, and nine are filled with nuts. What is the probability that one chocolate chosen at random is filled with caramel or nuts?
Click here to see answer by checkley77(12569) |
Question 211219: Please someone help be solve this problem I am lost need the step by step solution.
The odds against Lightning winning the third race are 9:4. If Sally places an $8 bet on Lightning to win and Lightning wins, find Sally's net winnings.
A)$2.25 B)$36 C)$18.00 D)$9.00 E)$72
Click here to see answer by Theo(3458)  |
Question 211228: Need Help with this one I'm stuck here anybody know the solution.
The last 50 violent crimes committed in Maryville werre 9 homocides, 24 robberies, and 17 assaults. What is the empirical probability that the next violent crime committed in Maryville will be an assault?
Click here to see answer by Theo(3458)  |
Question 211228: Need Help with this one I'm stuck here anybody know the solution.
The last 50 violent crimes committed in Maryville werre 9 homocides, 24 robberies, and 17 assaults. What is the empirical probability that the next violent crime committed in Maryville will be an assault?
Click here to see answer by Earlsdon(6287) |
Question 211221: HELP! me find the solution to this problem Please.
An independent television station airs a movie-of-the-day every Tuesday and Thursday. Their market research shows that their suspense movies are viewed by an average of 3500 people, their comedies are viewed by 4500 people, and their dramas are viewed by 6000 people. The station buys a package of 100 miview, consisting of 15 suspense movies, 40 comedies, and 45 dramas. The movie will be shown two per week for 50 weeks. Find the expected number of viewers on a fiven movie.
A)4667 B)479 C)140 D)5025 E)1400
Click here to see answer by stanbon(57285) |
Question 211229: Hello out there does anybody have the solution to this I am racking my brains out
Researchers find that the 2004 population of Califonia was 35,893,799, the 2004 population of Pennsylvania was 12,496,292, and the total US population was 293,655,404. What is the probability that a randomly selected US resident did not live in California? Round to the nearest thousandth of a percent?
Click here to see answer by Theo(3458)  |
Question 211235: HELP! these probability questions are driving me nuts. please show me the solution to this one.
1000 raffle tickets are sold at $3 each. One grand prize of $100 and two consolation prozes of $75 will be awarded. Find Jake's expectationif he purchases one ticket.
A) -$2.75 B) -$3.00 C) $0.24 D)$2.75 E) $3.00
Click here to see answer by stanbon(57285) |
Question 211217: I am stuck here please could someone help me with the solution with this one
Researchers find that the 2004 population of California was 35,893,799, the 2004 population of Pennsylvania was 12,406,292, and the total United States population was 293,655,404. What is the probability that a randomly selected United States resident did not live in California? Round to the nearest thousandth of a percent.
Click here to see answer by stanbon(57285) |
Question 211216: I am lost with this one please show me the solution to this problem
The last 50 viloent crimes committed in Maryville were 9 homocides, 24 robberies and 17 assaults. What is the empirical probability that the next violent crime committed in Maryville will be an assault?
Click here to see answer by stanbon(57285) |
Question 211119: Based on the information given for each of the following studies, decide
whether to reject the null hypothesis. For each, give the Z-score cutoff (or cutoffs)
on the comparison distribution at which the null hypothesis should be rejected,
the Z score on the comparison distribution for the sample score, and
your conclusion. Assume that all populations are normally distributed
Population
Sample Tails
Study μ σ Score p of Test
A 5 1 7 .05 1 (high predicted)
B 5 1 7 .05 2
C 5 1 7 .01 1 (high predicted)
D 5 1 7 .01 2
Click here to see answer by stanbon(57285) |
Question 211313: Chebyshev's theorem and the empirical rule
A sociologist studying the justice system has just written a paper detailing her findings after she examined the records of thousands of inmates. Among other things, she looked at the prison terms actually served by inmates who had been sentenced to five to ten years for a felony conviction. She found that the mean term actually served by those inmates was 46 months, with a standard deviation of 12 months. Suppose that these measures are valid for the population of all inmates who have been sentenced to five to ten years for a felony conviction. Complete the following statements about the distribution of all prison terms actually served by inmates sentenced to five to ten years for a felony conviction.
Click here to see answer by stanbon(57285) |
Question 211330:
Section 6.1: Confidence Intervals for the Mean (Large Samples)
1. Find the critical value zc necessary to form a confidence interval at the given level of confidence. (References: definition for level of confidence page 311, end of section exercises 5 – 8 page 317)
a. 95%
b. 75%
2. The new Twinkle bulb has a mean life of hours with a standard deviation hours. A random sample of 50 light bulbs is selected from inventory. The sample mean was found to be 500 hours.
a. Find the margin of error E for a 95% confidence interval.
Round your answer to the nearest hundredths.
b. Construct a 95% confidence interval for the mean life, of all Twinkle bulbs. (References: example 5 page 315, end of section exercises 51 - 56 pages 319 - 320)
Answer: a.
b.
3. A standard placement test has a mean of 115 and a standard deviation of = 10. Determine the minimum sample size if we want to be 95% certain that we are within 3 points of the true mean. (References: example 6 page 316, end of section exercises 58 - 62 pages 321 - 322)
Section 6.2: Confidence Intervals for the Mean (Small Samples)
4. An experimental egg farm is raising chickens to produce low cholesterol eggs. A lab tested 16 randomly selected eggs and found that the mean amount of cholesterol was 190 mg. The sample standard deviation was found to be s = 18.0 mg on this group. Assume that the population is normally distributed. (References: example 2 and 3 pages 327 - 328, end of section exercises 5 - 16 pages 330 - 331)
a. Find the margin of error for a 95% confidence interval. Round your answer to the nearest tenths.
b. Find a 95% confidence interval for the mean cholesterol content for all experimental eggs. Assume that the population is normally distributed.
Section 6.3: Confidence Intervals for Population Proportions
5. The new Twinkle bulb is being developed to last more than 1000 hours. A random sample of 100 of these new bulbs is selected from the production line. It was found that 64 lasted more than 1000 hours. Find the point estimate for the population proportion, the margin of error for a 95% confidence interval and then construct to the 95% confidence interval for the population proportion.
a. Find the margin of error E.
b. Construct a 95% confidence interval for the population proportion p of all Twinkle bulbs.
Click here to see answer by stanbon(57285) |
Question 208250: An independent testing agency has been contracted to determine whether there is any difference in gasoline mileage output of two different gasolines used in the same model automobile. The first gasoline was tested on 200 cars and produced a sample average of 18.5 miles per gallon with a standard deviation of 4.6 miles per gallon. The second was tested on a sample of 100 cars and produced a sample average of 19.34 miles per gallon with a standard deviation of 5.2 miles per gallon. At the .05 level of significance, is there evidence of a difference in performance of the two gasolines?
Click here to see answer by stanbon(57285) |
Question 208249: The personnel director of a large insurance company is interested in reducing the turnover rate of data processing clerks in the first year of employment. Past records indicate that 25% of all new hires in this area are no longer employed at the end of one year. Extensive new training approaches are implemented for a sample of 150 new data processing clerks.
At the end of a one-year period, 29 of these 150 individuals are no longer employed. At the .01 level of significance, is there evidence that the proportion of data processing clerks who have gone through the new training and are no longer employed is less than .25?
Click here to see answer by stanbon(57285) |
Question 211492: A case of 24 cans contains 1 can that is contaminated. Three cans are to be chosen randomly for testin.
A. How many different combinations of 3 cans could be selected?
B. What is the probability that the contaminate can is selected for testing?
Click here to see answer by stanbon(57285) |
Question 208248: A quality control expert is called in to determine whether a newly installed machine is producing a particular cotton cloth according to the specifications set by the manufacturer. The mean warp-breaking strength of this particular cotton cloth has been established to be 66 pounds.
A random sample of 36 pieces of cotton cloth is obtained from a production run on this machine. The results of the sample reveal a mean warp-breaking strength of 64.5 pounds and a standard deviation of 5 pounds. Can the quality control expert say that the cotton produced on the new machine meets the warp-breaking specification of the manufacturer at the .05 level of significance?
Click here to see answer by stanbon(57285) |
Question 211641: can anybody help with this one I can't get the solution
During the last hour, a telemarketer dialed 25 numbers and reached 7 busy signals, 3 answering machines, and 15 people. Use the information to determine the empirical probability that thenext call will be answered in person.
Click here to see answer by stanbon(57285) |
Question 211863: 5. The new Twinkle bulb is being developed to last more than 1000 hours. A random sample of 100 of these new bulbs is selected from the production line. It was found that 48 lasted more than 1000 hours. Find the point estimate for the population proportion, the margin of error for a 95% confidence and then construct to the 95% confidence interval for the population proportion p.
a. Find the margin of error E. (2.5 points)
Round E to three decimal places
b. Construct a 95% confidence interval for the population proportion p of all Twinkle bulbs. (2.5 points)
Click here to see answer by stanbon(57285) |
Question 212125: An ordinary (fair) die is a cube with the numbers through on the sides (represented by painted spots). Imagine that such a die is rolled twice in succession and that the face values of the two rolls are added together. This sum is recorded as the outcome of a single trial of a random experiment.
Compute the probability of each of the following events:
Event : The sum is greater than .
Event : The sum is not divisible by and not divisible by .
Round your answers to at least two decimals places.
Click here to see answer by stanbon(57285) |
Question 212116: Gender of Children: Constructing Sample Space. This section included a table summarizing the gender outcomes for a couple planning to have three children.
a. Construct a similar table for a couple planning to have four children
b. Assuming that the putcomes listed in part (a) are equally likely, find the probability of getting exactly two girls and two boys.
c. Find the probability that the four children are all boys
Click here to see answer by stanbon(57285) |
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Older solutions: 1..45, 46..90, 91..135, 136..180, 181..225, 226..270, 271..315, 316..360, 361..405, 406..450, 451..495, 496..540, 541..585, 586..630, 631..675, 676..720, 721..765, 766..810, 811..855, 856..900, 901..945, 946..990, 991..1035, 1036..1080, 1081..1125, 1126..1170, 1171..1215, 1216..1260, 1261..1305, 1306..1350, 1351..1395, 1396..1440, 1441..1485, 1486..1530, 1531..1575, 1576..1620, 1621..1665, 1666..1710, 1711..1755, 1756..1800, 1801..1845, 1846..1890, 1891..1935, 1936..1980, 1981..2025, 2026..2070, 2071..2115, 2116..2160, 2161..2205, 2206..2250, 2251..2295, 2296..2340, 2341..2385, 2386..2430, 2431..2475, 2476..2520, 2521..2565, 2566..2610, 2611..2655, 2656..2700, 2701..2745, 2746..2790, 2791..2835, 2836..2880, 2881..2925, 2926..2970, 2971..3015, 3016..3060, 3061..3105, 3106..3150, 3151..3195, 3196..3240, 3241..3285, 3286..3330, 3331..3375, 3376..3420, 3421..3465, 3466..3510, 3511..3555, 3556..3600, 3601..3645, 3646..3690, 3691..3735, 3736..3780, 3781..3825, 3826..3870, 3871..3915, 3916..3960, 3961..4005, 4006..4050, 4051..4095, 4096..4140, 4141..4185, 4186..4230, 4231..4275, 4276..4320, 4321..4365, 4366..4410, 4411..4455, 4456..4500, 4501..4545, 4546..4590, 4591..4635, 4636..4680, 4681..4725, 4726..4770, 4771..4815, 4816..4860, 4861..4905, 4906..4950, 4951..4995, 4996..5040, 5041..5085, 5086..5130, 5131..5175, 5176..5220, 5221..5265, 5266..5310, 5311..5355, 5356..5400, 5401..5445, 5446..5490, 5491..5535, 5536..5580, 5581..5625, 5626..5670, 5671..5715, 5716..5760, 5761..5805, 5806..5850, 5851..5895, 5896..5940, 5941..5985, 5986..6030, 6031..6075, 6076..6120, 6121..6165, 6166..6210, 6211..6255, 6256..6300, 6301..6345, 6346..6390, 6391..6435, 6436..6480, 6481..6525, 6526..6570, 6571..6615, 6616..6660, 6661..6705, 6706..6750, 6751..6795, 6796..6840, 6841..6885, 6886..6930, 6931..6975, 6976..7020, 7021..7065, 7066..7110, 7111..7155, 7156..7200, 7201..7245, 7246..7290, 7291..7335, 7336..7380, 7381..7425, 7426..7470, 7471..7515, 7516..7560, 7561..7605, 7606..7650, 7651..7695, 7696..7740, 7741..7785, 7786..7830, 7831..7875, 7876..7920, 7921..7965, 7966..8010, 8011..8055, 8056..8100, 8101..8145, 8146..8190, 8191..8235, 8236..8280, 8281..8325, 8326..8370, 8371..8415, 8416..8460, 8461..8505, 8506..8550, 8551..8595, 8596..8640, 8641..8685, 8686..8730, 8731..8775, 8776..8820, 8821..8865, 8866..8910, 8911..8955, 8956..9000, 9001..9045, 9046..9090, 9091..9135, 9136..9180, 9181..9225, 9226..9270, 9271..9315, 9316..9360, 9361..9405, 9406..9450, 9451..9495, 9496..9540, 9541..9585, 9586..9630, 9631..9675, 9676..9720, 9721..9765, 9766..9810, 9811..9855, 9856..9900, 9901..9945, 9946..9990, 9991..10035, 10036..10080, 10081..10125, 10126..10170, 10171..10215, 10216..10260, 10261..10305, 10306..10350, 10351..10395, 10396..10440, 10441..10485, 10486..10530, 10531..10575, 10576..10620, 10621..10665, 10666..10710, 10711..10755, 10756..10800, 10801..10845, 10846..10890, 10891..10935, 10936..10980, 10981..11025, 11026..11070, 11071..11115, 11116..11160, 11161..11205, 11206..11250, 11251..11295, 11296..11340, 11341..11385, 11386..11430, 11431..11475, 11476..11520, 11521..11565, 11566..11610, 11611..11655, 11656..11700, 11701..11745, 11746..11790, 11791..11835, 11836..11880, 11881..11925, 11926..11970, 11971..12015, 12016..12060, 12061..12105, 12106..12150, 12151..12195, 12196..12240, 12241..12285, 12286..12330, 12331..12375, 12376..12420, 12421..12465, 12466..12510, 12511..12555, 12556..12600, 12601..12645, 12646..12690, 12691..12735, 12736..12780, 12781..12825, 12826..12870, 12871..12915, 12916..12960, 12961..13005, 13006..13050, 13051..13095, 13096..13140, 13141..13185, 13186..13230, 13231..13275, 13276..13320, 13321..13365, 13366..13410, 13411..13455, 13456..13500, 13501..13545, 13546..13590, 13591..13635, 13636..13680, 13681..13725, 13726..13770, 13771..13815, 13816..13860, 13861..13905, 13906..13950, 13951..13995, 13996..14040, 14041..14085, 14086..14130, 14131..14175, 14176..14220, 14221..14265, 14266..14310, 14311..14355, 14356..14400, 14401..14445, 14446..14490, 14491..14535, 14536..14580, 14581..14625, 14626..14670, 14671..14715, 14716..14760, 14761..14805, 14806..14850, 14851..14895, 14896..14940, 14941..14985, 14986..15030, 15031..15075, 15076..15120, 15121..15165, 15166..15210, 15211..15255, 15256..15300, 15301..15345, 15346..15390, 15391..15435, 15436..15480, 15481..15525, 15526..15570, 15571..15615, 15616..15660, 15661..15705, 15706..15750, 15751..15795, 15796..15840, 15841..15885, 15886..15930, 15931..15975, 15976..16020, 16021..16065, 16066..16110, 16111..16155, 16156..16200, 16201..16245, 16246..16290, 16291..16335, 16336..16380, 16381..16425, 16426..16470, 16471..16515, 16516..16560, 16561..16605, 16606..16650, 16651..16695, 16696..16740, 16741..16785, 16786..16830, 16831..16875, 16876..16920, 16921..16965, 16966..17010, 17011..17055, 17056..17100, 17101..17145, 17146..17190, 17191..17235, 17236..17280, 17281..17325, 17326..17370, 17371..17415, 17416..17460, 17461..17505, 17506..17550, 17551..17595, 17596..17640, 17641..17685, 17686..17730, 17731..17775, 17776..17820, 17821..17865, 17866..17910, 17911..17955, 17956..18000, 18001..18045, 18046..18090, 18091..18135, 18136..18180, 18181..18225, 18226..18270, 18271..18315, 18316..18360, 18361..18405, 18406..18450, 18451..18495, 18496..18540, 18541..18585, 18586..18630, 18631..18675, 18676..18720, 18721..18765, 18766..18810, 18811..18855, 18856..18900, 18901..18945, 18946..18990, 18991..19035, 19036..19080, 19081..19125, 19126..19170, 19171..19215, 19216..19260, 19261..19305, 19306..19350, 19351..19395, 19396..19440, 19441..19485, 19486..19530, 19531..19575, 19576..19620, 19621..19665, 19666..19710, 19711..19755, 19756..19800, 19801..19845, 19846..19890, 19891..19935, 19936..19980, 19981..20025, 20026..20070, 20071..20115, 20116..20160, 20161..20205, 20206..20250, 20251..20295, 20296..20340, 20341..20385, 20386..20430, 20431..20475, 20476..20520, 20521..20565, 20566..20610, 20611..20655, 20656..20700, 20701..20745, 20746..20790, 20791..20835, 20836..20880, 20881..20925, 20926..20970, 20971..21015, 21016..21060, 21061..21105, 21106..21150, 21151..21195
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