Tutors Answer Your Questions about Probability-and-statistics (FREE)
Question 136632: 3. The same production manager in question 1 above decides to use a smaller sample size of just 25 items. If she conducts a 2-tailed test at the 90 percent level of confidence, her critical value(s) would be: ________
4. National Packing Materials Company claims its X20 box can hold loads up to at least 80 pounds. Smith Widget Company has been using the boxes for one year and feels the boxes fail at lighter loads. Hearing the complaints from Smith, the lead engineer for National Packaging decides to test the company’s claim that it can hold at least 80 pounds. He decides to text 64 boxes at the .05 level of significance. He finds a mean of 78 pounds with a standard deviation of 5 pounds. What is the critical value for this test?_______ What is the value of the test statistic? ___________ What is the Null hypothesis? ___________ What is the alternate hypothesis? ____________ What is the standard error of the mean? ______________ Should the Null hypothesis be accepted or rejected? __________
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Question 136635: 8. A technique used to arrive at the regression equation by minimizing the sum of the squares of the vertical differences between the actual Y values and the predicted Y values is known as the ______________.
9. A condition that occurs in multiple regression analysis if the independent variables are themselves correlated is known as: a. autocorrelation b. stepwise regression
c. multicorrelation d. multicollinearity
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Question 136605: In a Texas study, researchers gave lovastatin to 2,325 people and an inactive substitute to 2,081 people (average age 58). After 5 years, 57 of the lovastatin group had suffered a heart attack, compared with 97 for the inactive pill.
(a) State the appropriate hypotheses.
(b) Obtain a test statistic and p-value. Interpret the results at α = .01.
(c) Is normality assured?
(d) Is the difference large enough to be important?
(e) What else would medical researchers need to know before prescribing this drug widely?
Click here to see answer by stanbon(57347) |
Question 136827: 1)A weight-loss clinic guarantees that its new customers will lose at least 5 lb by the end of their first month of participation or their money will be refunded. If the loss of weight of customers at the end of their first month is normally distributed, with a mean of 6.8 lb and a standard deviation of 0.81 lb, find the percent of customers who will be able to claim a refund.
Please Help!
Click here to see answer by stanbon(57347) |
Question 136825: a)Find the standard deviation of the following set of data.
180, 187, 175, 186, 177, 196, 166
b)The results on an English exam are normally distributed. the z-scores for some of the students are shown below.
Jan 1.3 Kim 1.8 Lou -1.1 May 0.0
Nan 1.1 Fay -1.7 Gia 1.1 Sue -1.8
Which of the students scored below the mean?
Thanka in advance
Click here to see answer by stanbon(57347) |
Question 136824: A newspaper article reported that people spend a mean of hours per day watching TV, with a standard deviation of hours. A psychologist would like to conduct interviews with the of the population who spend the most time watching TV. She assumes that the daily time people spend watching TV is normally distributed. At least how many hours of daily TV watching are necessary for a person to be eligible for the interview? Carry your intermediate computations to at least four decimal places. Round your answer to at least one decimal place.
Click here to see answer by stanbon(57347) |
Question 136796: Not sure about this!
An auditor reviewed 25 oral surgery insurance claims from a particular surgical office, determining that the mean out-of-pocket patient billing above the reimbursed amount was $275.66 with a standard deviation of $78.11.
(a) At the 5 percent level of significance, does this sample prove a violation of the guideline that the average patient should pay no more than $250 out-of-pocket?
State your hypotheses and decision rule.
(b) Is this a close decision?
Click here to see answer by stanbon(57347) |
Question 136792: 9.54 - Please solve
Faced with rising fax costs, a firm issued a guideline that transmissions of 10 pages or more should be sent by 2-day mail instead. Exceptions are allowed, but they want the average to be 10 or below. The firm examined 35 randomly chosen fax transmissions during the next year, yielding a sample mean of 14.44 with a standard deviation of 4.45 pages. (a) At the .01 level of significance, is the true mean greater than 10? (b) Use Excel to find the right-tail p-value.
Click here to see answer by stanbon(57347) |
Question 136834: A newspaper spent a mean of 7.5 hours watching tv per day with a standard deviation of 2.1 hours. A psychologisit conducted interviews with 10% of the population who watched tv. She assumes that the tim watching tv is normally distributed. How many hours of daily tv is ncessary for a person to be eligible for the interview. Carry your intermediate comoputations to at least four decimal places. Round your answer to at least one decimal place.
Thank you.
Click here to see answer by stanbon(57347) |
Question 136794: Need assistance with this -
The Web-based company Oh Baby! Gifts has a goal of processing 95 percent of its orders on the same day they are received. If 485 out of the next 500 orders are processed on the same day, would this prove that they are exceeding their goal, using α = .025? (See story.news.yahoo.com accessed June 25, 2004.)
Click here to see answer by stanbon(57347) |
Question 136842: Suppose that the heights of adult women in the United States are normally distributed with a mean of 63.5 inches and a standard deviation of 2.3inches. Jennifer is taller than 75%of the population of U.S. women. How tall (in inches) is Jennifer? Carry your intermediate computations to at least four decimal places. Round your answer to at least one decimal place.
Thanks,
Click here to see answer by stanbon(57347) |
Question 136858: 8. a football coach has five guards and seven tackles trying out for the squad.as a final cut, five of these players will be cut at random. find the probablity that the group of players cut will
a. consist of guards only
b. consist of tackles only
c. consist of three guards and two tackles
d.consist of four tackles and one guard
e. consist of three tackles and two guards
f. consist of four guards and one tackle
10. a case of soda pop contains six bottles of root beer, six bottles of orange soda, seven bottles of cola, and five bottles of gingerale. If you select three bottles at random find the probability that
a. all three bottles are cola
b. all three bottles are rootbeer
c. two bottles are gingerale and one bottle is cola
d. one bottle is orange soda, and two bottles are rootbeer
e. one bottle is cola, one bottle is orange soda, and one bottle is gingerale
f. one bottle is cola, one bottle is orange soda, and one bottle is rootbeer
Click here to see answer by stanbon(57347) |
Question 136805: Need help having problems solving this problem
The engineer in a widget factory wants to test out a new form of raw materials. So a batch of widgets are made in the old manner as a control group and then a batch are made with the new materials as a comparison. If the widget weight is statistically the same on both sets, the new materials will be used. The weights of the 10 old process widgets and the 10 new process widgets are seen below.
Old New
36.19 36.20
35.80 36.62
36.00 36.03
36.19 36.40
36.18 36.44
36.11 36.02
36.13 36.12
36.48 36.56
35.98 36.05
36.40 36.44
1. Define this situation as either a 2 sample test or a paired test. Why?
2. Calculate a test statistic
3. Calculate a p-value
1. Give an accurate statement as to whether or not the new widget material should be used. Use a significance level of 0.05.
Click here to see answer by stanbon(57347) |
Question 136942: I am working on this problem and I would like to see if I had worked it out correctly. Could you please help me. So I may continue to work the others problem.
Question: A football coach has five guards and seven tackles trying out for the squad. As a final cut, five of these players will be cut at random. Find the probability that the group of players cut will
a. Consist of guards only
b. Consist of tackles only
c. Consist of three guards and two tackles
d. Consist of four tackles ans one guard
e. Consist of three tackles and two guards
f. Consist fo four guards and one tackle
My answer are:
A. 5/5= 1
b. 5/7
c. 3/5 * 2/7 = 6/35
d. 4/7 * 1/5 = 4/35
e. 3/7 * 2/5 = 6/35
f. 4/5 * 1/7 = 4/35
Click here to see answer by stanbon(57347) |
Question 136833: The prices of the 21 top-rated 28-inch direct view television sets are as follows.
230, 320, 450, 550, 640, 710, 810,
270, 370, 470, 560, 670, 760, 820,
310, 420, 520, 600, 680, 810, 860
Determine Q1
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Question 136793: Looking for help!
A coin was flipped 60 times and came up heads 38 times. (a) At the .10 level of significance, is the coin biased toward heads? Show your decision rule and calculations. (b) Calculate a p-value and interpret it.
Thanks
Click here to see answer by stanbon(57347) |
Question 137008: 1)A six-sided die is rolled 30 times and the numbers 1 through 6 appear as shown in the
following frequency distribution. At the .10 significance level, can we conclude that the die
is fair?
Outcome Frequency Outcome Frequency
1 3 4 3
2 6 5 9
3 2 6 7
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Question 137006: 1)The null hypothesis and the alternate are:
H0: The cell categories are equal.
H1: The cell categories are not equal.
Category fo
A 10
B 20
C 30
a. State the decision rule, using the .05 significance level.
b. Compute the value of chi-square.
c. What is your decision regarding H0?
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Question 137014: The chief of security for the Mall of the Dakotas was directed to study the problem of missing goods. He selected a sample of 100 boxes that had been tampered with and ascertained that for 60 of the boxes, the missing pants, shoes, and so on were attributed to shoplifting. For 30 other boxes employees had stolen the goods, and for the remaining 10 boxes he blamed poor inventory control.
In his report to the mall management, can he say that shoplifting is twice as likely to be the cause of the lossas compared with either employee theft or poor inventory control and that employee theft and poor inventory control are equally likely? Use the 0.02 level.
Click here to see answer by stanbon(57347) |
Question 137037: 1)School planners in 1995 gave the following planning estimates for the growth of the student population for the next 9 years. Perform a goodness of fit to see if their estimates were accurate.
Planning Year
Actual Size
Expected
Size
1Planning Year
798Actual Size
798Expected Size
2Planning Year
876Actual Size
872Expected Size
3Planning Year
950Actual Size
955Expected Size
4Planning Year
1044Actual Size
1046Expected Size
5Planning Year
1025Actual Size
1144Expected Size
6Planning Year
1232Actual Size
1254Expected Size
7Planning Year
1477Actual Size
1371Expected Size
8Planning Year
1531Actual Size
1503Expected Size
9Planning Year
1655Actual Size
1645Expected Size
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Question 137022: n how many ways can Al, Bob, Carlos, Don, Ed, and Fern be seated in a row of six seats if Al and Bob are not to be seated side by side? [Hint: Either Al and Bob will be seated side by side or they will not be seated side by side.]
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Question 137019: The license plates for a certain state consist of two letters followed by a five - digit number such that the first digit of the number is not zero. An example for two letters and four digits is PK-2446. (If the problem has no solution, enter NONE in the answer box.)
(a) How many different license plates can be produced?
(b) How many different plates do not have a repeated letter?
(c) How many plates do not have any repeated digits in the number part of the plate?
(d) How many plates do not have a repeated letter and also do not have any repeated digits?
Click here to see answer by stanbon(57347) |
Question 137046: A random sample of n=64 observations has a mean x(bar)=29.1 and a standard deviation s=3.9.
a) Give the point estimate of the population mean mu and find the margin of error for your estimate.
b) Find a 90% confidence interval for mu. what does "90% confident" mean?
c) Find a 90% lower confidence bound for the population mean mu. Why is this bound different from the lower confidence limit in part b?
d) How many observations do you need to estimate mu to within .5, with probability equal to .95?
Click here to see answer by stanbon(57347) |
Question 137180: Suppose that follows a chi-square distribution with degrees of freedom. Compute . Round your answer to at least three decimal places.
Suppose again that follows a chi-square distribution with degrees of freedom. Find such that . Round your answer to at least two decimal places.
Find the median of the chi-square distribution with degrees of freedom. Round your answer to at least two decimal places.
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Question 137200: A bag contains three red balls, five white balls and two green balls. If three balls are selected at random, with replacement, find the probability that the first two are red and the third one is green.
Click here to see answer by oscargut(891)  |
Question 137223: 1. Suppose we are testing the difference between two proportions at the 0.05 level of significance. If the computed z is –1.07, what is our decision?
A) Reject the null hypothesis
B) Do not reject the null hypothesis
C) Take a larger sample
D) Reserve judgment
2. Suppose that an automobile manufacturer designed a radically new lightweight engine and wants to recommend the grade of gasoline that will have the best fuel economy. The four grades are: regular, below regular, premium, and super premium. The test car made three trial runs on the test track using each of the four grades and the miles per gallon recorded. At the 0.05 level, what is the critical value of F used to test the hypothesis that the miles per gallon for each fuel is the same.
Kilometers per liter
Regular Below Regular Premium Super Premium
39.31 36.69 38.99 40.04
39.87 40.00 40.02 39.89
39.87 41.01 39.99 39.93
A) 1.96
B) 4.07
C) 2.33
D) 12.00
3. Three different fertilizers were applied to a field of celery. In computing F, how many degrees of freedom are there in the numerator?
A) 0
B) 1
C) 2
D) 3
4. Suppose a package delivery company purchased 14 trucks at the same time. Five trucks were purchased from manufacturer A, four from B and five from manufacturer C. The cost of maintaining each truck was recorded. The company used ANOVA to test if the mean maintenance cost of the trucks from each manufacturer were equal. To apply the F test, how many degrees of freedom are in the denominator?
A) 2
B) 3
C) 11
D) 14
5. In ANOVA, an F statistic is used to test a null hypothesis such as:
A)
B)
C)
D)
6. An electronics company wants to compare the quality of their cell phones to the cell phones from three competitors. They sample 10 phones from each company and count the number of defects for each phone. If ANOVA were used to compare the average number of defects, the treatments would be defined as:
A) the number of cell phones sampled.
B) the average number of defects.
C) The total number of phones
D) The four companies.
7. The chi-square distribution can assume
A) only positive values.
B) only negative values.
C) negative and positive values or zero.
D) only zero.
8. A sample of 100 production workers is obtained. The workers are classified by gender (male, female) and by age (under 20, 20–29, 30–39 and 40 or over). How many degrees of freedom are there?
A) 0
B) 3
C) 6
D) 5
9. For any chi-square goodness-of-fit problem, the number of degrees of freedom is found by
A) n – k – 1.
B) k – 1.
C) n + 1.
D) n + k.
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Question 137258: Biting an unpopped kernel of popcorn hurts! As an experiment, a self-confessed connoisseur of
cheap popcorn carefully counted 773 kernels and put them in a popper. After popping, the unpopped
kernels were counted. There were 86. (a) Construct a 90 percent confidence interval for the proportion
of all kernels that would not pop. (b) Check the normality assumption. (c) Try the Very Quick
Rule. Does it work well here? Why, or why not? (d) Why might this sample not be typical?
Click here to see answer by stanbon(57347) |
Question 137257: A sample of 20 pages was taken without replacement from the 1,591-page phone directory
Ameritech Pages Plus Yellow Pages. On each page, the mean area devoted to display ads was measured
(a display ad is a large block of multicolored illustrations, maps, and text). The data (in
square millimeters) are shown below:
0 260 356 403 536 0 268 369 428 536
268 396 469 536 162 338 403 536 536 130
(a) Construct a 95 percent confidence interval for the true mean. (b) Why might normality be an
issue here? (c) What sample size would be needed to obtain an error of ±10 square millimeters
with 99 percent confidence? (d) If this is not a reasonable requirement, suggest one that is.
Click here to see answer by stanbon(57347) |
Question 137285: A study regarding the relationship between age and the amount of pressure sales personnel feel in relation to their jobs revealed the following sample information. At the .01 significance level, is there a relationship between job pressure and age.
Degree of Job Pressure
Age (years) Low Medium High
Less than 25 20 18 22
25 up to 40 50 46 44
40 up to 60 58 63 59
60 and older 34 43 43
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Question 137288: A $100, $50, $20 prize are to awarded to three different people. If eight people are being considered for the prizes, how many different arragements are possible? My answer is:
P(100, 50, 20)= P(100)P(50)P(20) = (100/170)(50/170)(20/170)=100000/170 = 588.2352941/8 = 73.5
Click here to see answer by stanbon(57347) |
Question 137281: There are four auto body shops in a community and all claim to promptly serve customers. To check if there is any difference in service, customers are randomly selected from each repair shop and their waiting times in days are recorded. The output from a statistical software package is:
Summary
Groups Count Sum Average Variance
Body Shop A 3 15.4 5.133333 0.323333
Body Shop B 4 32 8 1.433333
Body Shop C 5 25.2 5.04 0.748
Body Shop D 4 25.9 6.475 0.595833
ANOVA
Source of Variation SS df M F p-value
Between Groups 23.37321 3 7.791069 9.612506 0.001632
Within Groups 9.726167 12 0.810514
Total 33.09938 15
Is there evidence to suggest a difference in the mean waiting times at the four body shops?
Use the .05 significance level.
Click here to see answer by stanbon(57347) |
Question 137289: You are given a multiple choice test consisting of 10 questions. Each question has 4 choices. If you quess at all of the answers, what is the probability that you will choose the incorrect answer ofr each question? My answer is:
4 * 10 = 40 40/10 = 4%
Click here to see answer by stanbon(57347) |
Question 137289: You are given a multiple choice test consisting of 10 questions. Each question has 4 choices. If you quess at all of the answers, what is the probability that you will choose the incorrect answer ofr each question? My answer is:
4 * 10 = 40 40/10 = 4%
Click here to see answer by oscargut(891) |
Question 137291: Confused...Please Help!
The probability that a student has a Visa card (event V) is .70. The probability that a student has a
MasterCard (event M) is .60. The probability that a student has both cards is .50. (a) Find the probability
that a student has either a Visa card or a MasterCard. (b) In this problem, are V and M independent?
Explain.
Click here to see answer by stanbon(57347) |
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7606..7650, 7651..7695, 7696..7740, 7741..7785, 7786..7830, 7831..7875, 7876..7920, 7921..7965, 7966..8010, 8011..8055, 8056..8100, 8101..8145, 8146..8190, 8191..8235, 8236..8280, 8281..8325, 8326..8370, 8371..8415, 8416..8460, 8461..8505, 8506..8550, 8551..8595, 8596..8640, 8641..8685, 8686..8730, 8731..8775, 8776..8820, 8821..8865, 8866..8910, 8911..8955, 8956..9000, 9001..9045, 9046..9090, 9091..9135, 9136..9180, 9181..9225, 9226..9270, 9271..9315, 9316..9360, 9361..9405, 9406..9450, 9451..9495, 9496..9540, 9541..9585, 9586..9630, 9631..9675, 9676..9720, 9721..9765, 9766..9810, 9811..9855, 9856..9900, 9901..9945, 9946..9990, 9991..10035, 10036..10080, 10081..10125, 10126..10170, 10171..10215, 10216..10260, 10261..10305, 10306..10350, 10351..10395, 10396..10440, 10441..10485, 10486..10530, 10531..10575, 10576..10620, 10621..10665, 10666..10710, 10711..10755, 10756..10800, 10801..10845, 10846..10890, 10891..10935, 10936..10980, 10981..11025, 11026..11070, 11071..11115, 11116..11160, 11161..11205, 11206..11250, 11251..11295, 11296..11340, 11341..11385, 11386..11430, 11431..11475, 11476..11520, 11521..11565, 11566..11610, 11611..11655, 11656..11700, 11701..11745, 11746..11790, 11791..11835, 11836..11880, 11881..11925, 11926..11970, 11971..12015, 12016..12060, 12061..12105, 12106..12150, 12151..12195, 12196..12240, 12241..12285, 12286..12330, 12331..12375, 12376..12420, 12421..12465, 12466..12510, 12511..12555, 12556..12600, 12601..12645, 12646..12690, 12691..12735, 12736..12780, 12781..12825, 12826..12870, 12871..12915, 12916..12960, 12961..13005, 13006..13050, 13051..13095, 13096..13140, 13141..13185, 13186..13230, 13231..13275, 13276..13320, 13321..13365, 13366..13410, 13411..13455, 13456..13500, 13501..13545, 13546..13590, 13591..13635, 13636..13680, 13681..13725, 13726..13770, 13771..13815, 13816..13860, 13861..13905, 13906..13950, 13951..13995, 13996..14040, 14041..14085, 14086..14130, 14131..14175, 14176..14220, 14221..14265, 14266..14310, 14311..14355, 14356..14400, 14401..14445, 14446..14490, 14491..14535, 14536..14580, 14581..14625, 14626..14670, 14671..14715, 14716..14760, 14761..14805, 14806..14850, 14851..14895, 14896..14940, 14941..14985, 14986..15030, 15031..15075, 15076..15120, 15121..15165, 15166..15210, 15211..15255, 15256..15300, 15301..15345, 15346..15390, 15391..15435, 15436..15480, 15481..15525, 15526..15570, 15571..15615, 15616..15660, 15661..15705, 15706..15750, 15751..15795, 15796..15840, 15841..15885, 15886..15930, 15931..15975, 15976..16020, 16021..16065, 16066..16110, 16111..16155, 16156..16200, 16201..16245, 16246..16290, 16291..16335, 16336..16380, 16381..16425, 16426..16470, 16471..16515, 16516..16560, 16561..16605, 16606..16650, 16651..16695, 16696..16740, 16741..16785, 16786..16830, 16831..16875, 16876..16920, 16921..16965, 16966..17010, 17011..17055, 17056..17100, 17101..17145, 17146..17190, 17191..17235, 17236..17280, 17281..17325, 17326..17370, 17371..17415, 17416..17460, 17461..17505, 17506..17550, 17551..17595, 17596..17640, 17641..17685, 17686..17730, 17731..17775, 17776..17820, 17821..17865, 17866..17910, 17911..17955, 17956..18000, 18001..18045, 18046..18090, 18091..18135, 18136..18180, 18181..18225, 18226..18270, 18271..18315, 18316..18360, 18361..18405, 18406..18450, 18451..18495, 18496..18540, 18541..18585, 18586..18630, 18631..18675, 18676..18720, 18721..18765, 18766..18810, 18811..18855, 18856..18900, 18901..18945, 18946..18990, 18991..19035, 19036..19080, 19081..19125, 19126..19170, 19171..19215, 19216..19260, 19261..19305, 19306..19350, 19351..19395, 19396..19440, 19441..19485, 19486..19530, 19531..19575, 19576..19620, 19621..19665, 19666..19710, 19711..19755, 19756..19800, 19801..19845, 19846..19890, 19891..19935, 19936..19980, 19981..20025, 20026..20070, 20071..20115, 20116..20160, 20161..20205, 20206..20250, 20251..20295, 20296..20340, 20341..20385, 20386..20430, 20431..20475, 20476..20520, 20521..20565, 20566..20610, 20611..20655, 20656..20700, 20701..20745, 20746..20790, 20791..20835, 20836..20880, 20881..20925, 20926..20970, 20971..21015, 21016..21060, 21061..21105, 21106..21150, 21151..21195, 21196..21240
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