Tutors Answer Your Questions about Probability-and-statistics (FREE)
Question 644114: A bag contains "n"cards each having one of the numbers 1,2,3,4,.....n written on it. If all numbers are used the probability of drawing a card with a number less than or equal to 10 is 4/10. How many cards are in the bag?
Click here to see answer by stanbon(57387) |
Question 644208: 1. a box contains 3 yellow, 2 blue,and 4 red pencils. suppose you choose a pencil, replace, then choose another, find the probability of choosing yellow then red?
2. refer to problem above , find the probability of choosing blue then yellow?
3. suppose you chose a pencil from the box problem above, and then choose another pencil without replacing the first one. find probability of choosing blue, then red?
4. refer question above, find the probabilityof choosing yellow then blue
Click here to see answer by edjones(7569)  |
Question 644664: Trudy Green works for the True-Green Lawn Company. Her job is to solicit lawn-care business via the telephone. Listed beloware the number of appointments she made in each of the last 25 hours of calling.
9 5 2 6 5 6 44 7 2 3 6 3 44 7 8 4 4 5 54 8 33
what is the arithmetic mean number of appointments she made per hour? What is the median number of appointments per hour? Write a brief report summarizing the findings.
Click here to see answer by lynnlo(4164) |
Question 644782: Suppose a 10 item multiple choice test which has 5 choices for each questions was given passing grade of 10%. If a student who took the test did not study, what is the probability that student will pass if he guessed each and every question?
.THANKS!
Click here to see answer by colliefan(239) |
Question 644838: Please Help I am trying...
The following data lists the average monthly snowfall for January in 15 cities around the US:
13 15 26 24 44 4 20 37
31 3 47 21 13 28 23
Find the mean, variance, and standard deviation. Please show all of your work.
I have ...
Mean - 13+31+15+3+26+47+24+21+44+13+4+28+20+23+37=349/15=
Mean=23.27
Variance -
Can anyone help please?
Click here to see answer by ewatrrr(10682)  |
Question 644843: 11. Assume that the population of heights of female college students is approximately normally distributed with mean m of 66.24 inches and standard deviation s of 5.07 inches. A random sample of 72 heights is obtained. Show all work. -
(A) Find P(x>65.75)
(B) Find the mean and standard error of the xbar distribution
(C) Find P(xbar>65.75).
(D) Why is the formula required to solve (A) different than (C)?
Click here to see answer by ewatrrr(10682)  |
Question 644841: My last one I need help with please
Starting with the data values 70 and 100, add three data values to the sample so that the mean is 85, the median is 76, and the mode is 76. Please show all of your work.
I have this ...
Since the mode is 76, at least 2 of the values must be 76.
Mean = (1/9)(70 + 76 + 76 + x + 100) = 85
Click here to see answer by ewatrrr(10682)  |
Question 645487: A mall has 3 department stores, JC Penny's, Macy's, and Sears. A survey of 2,631 people exiting the mall found that 432 made a purchase at JC Penny's, 291 made a purchase at Macy's, 517 made a purchase at Sears, 83 made a purchase at JC Penny's and Macy's, 207 made a purchase at JC Penny and Sears, 126 of them made a purchase at Macy's and Sears, and 45 of them made a purchase at all 3 stores.
A. How many people made a purchase at JC Penney but did not make a purchase at Sears?
B. How many people made a purchase at exactly one of the three stores?
Thanks so much.
Click here to see answer by stanbon(57387) |
Question 387979: Information from the Department of Motor Vehicles
indicates that the average age of licensed drivers is
U= 39.7 years with a standard deviation of
O= 12.5 years. Assuming that the distribution of
drivers’ ages is approximately normal,
a. What proportion of licensed drivers are more than
50 years old?
b. What proportion of licensed drivers are less than
30 years old?
Click here to see answer by 555777(1) |
Question 646101: The weights of adult Asian palm civets are known to be normally distributed with
a mean of 7.7 pounds and a standard deviation of 0.95 pounds. What is the
probability that a randomly selected civet will:
A. Weigh at least 6 pounds?
B. Weigh less than 5 pounds or more than 10 pounds?
Please help, i'm so confused! thank you
Click here to see answer by ewatrrr(10682)  |
Question 646136: Based upon statistical studies it has been found that 0.19% of all births in the United States will result in triplets being born. If 29,700 births are selected at random what is the probability that:
A. At most 50 of them will result in triples being born?
B. Between 45-70 of them will result in triplets being born?
Please help, would be much appreciated
Click here to see answer by ewatrrr(10682)  |
Question 646174: According to the Internal Revenue Service, the mean tax for the year 2011
was $3,000. Assume the standard deviation is $410 and that the amounts follow
a normal probability distribution.
What percent of the refunds are less than $2,900 or greater than $3,200?
Click here to see answer by ewatrrr(10682)  |
Question 646121: During the 2002 soccer season, Maren Meinert of the Boston Breakers made approximately 2 goal points for every 5 of her shots on goal. What is the probability that Maren Meinert would make 2 goal points on two shots in a row during the 2002 season?
Click here to see answer by stanbon(57387) |
Question 646789: if you randomly select 3 cans of regular and diet cola, but assume that there are 8 cans of regular cola and 6 cans of diet cola.
(1) What is the probability that 3 cans of regular cola are selected?
(2) What is the probability that 0 cans of regular cola are selected, i.e.,
3 cans of diet cola are selected.?
(1) What is the probability that 2 cans of regular cola and 1 can of diet cola are selected?
Click here to see answer by ewatrrr(10682)  |
Question 646779: Rework problem 9 from section 2.3 of your text. Assume that you have 6 dimes and 5 quarters (all distinct), and you select 4 coins.
(1) In how many ways can the selection be made? 330
(2) In how many ways can the selection be made if all the coins are dimes? 15
(3) In how many ways can the selection be made if you select 2 dimes and 2 quarters? 150
(4) In how many ways can the selection be made so that at least 2 coins are dimes?
I'm confused on number four. I tied using 6c2+6c3+6c4 and multiplying the same set but none of the answers are right. I know the problem can be set up as total-less than two options but i dont know how to set up the permutiation or combination. I do understand how to visualize the problem though
Click here to see answer by ewatrrr(10682)  |
Question 646776: 7 cards are marked with a diferent number from 1-7, then placed face down on a table. One card is selected at random and not placed. A second card is then taken, at random . Determine the probabity that one card has an odd number on it.
This is the question I am unsure about. I found out that the probability for the first card that is picked up is 4/7 and for the second card the probability is 3/6 but I am not sure how to then use that info to get an answer to the writing above? Could you help?
Click here to see answer by ewatrrr(10682)  |
Question 646847: the resting heart rates for 10 members of a school's soccer team were measured by the school nurse.the results were the following (beats per min) :
55,58,47,62,64,61,56,60,63,65
compute the sample mean and round to the nearest tenth if necessary
Click here to see answer by ewatrrr(10682)  |
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17551..17595, 17596..17640, 17641..17685, 17686..17730, 17731..17775, 17776..17820, 17821..17865, 17866..17910, 17911..17955, 17956..18000, 18001..18045, 18046..18090, 18091..18135, 18136..18180, 18181..18225, 18226..18270, 18271..18315, 18316..18360, 18361..18405, 18406..18450, 18451..18495, 18496..18540, 18541..18585, 18586..18630, 18631..18675, 18676..18720, 18721..18765, 18766..18810, 18811..18855, 18856..18900, 18901..18945, 18946..18990, 18991..19035, 19036..19080, 19081..19125, 19126..19170, 19171..19215, 19216..19260, 19261..19305, 19306..19350, 19351..19395, 19396..19440, 19441..19485, 19486..19530, 19531..19575, 19576..19620, 19621..19665, 19666..19710, 19711..19755, 19756..19800, 19801..19845, 19846..19890, 19891..19935, 19936..19980, 19981..20025, 20026..20070, 20071..20115, 20116..20160, 20161..20205, 20206..20250, 20251..20295, 20296..20340, 20341..20385, 20386..20430, 20431..20475, 20476..20520, 20521..20565, 20566..20610, 20611..20655, 20656..20700, 20701..20745, 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